x^2+(k+1)x+4=0

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Solution for x^2+(k+1)x+4=0 equation:


Simplifying
x2 + (k + 1) * x + 4 = 0

Reorder the terms:
x2 + (1 + k) * x + 4 = 0

Reorder the terms for easier multiplication:
x2 + x(1 + k) + 4 = 0
x2 + (1 * x + k * x) + 4 = 0

Reorder the terms:
x2 + (kx + 1x) + 4 = 0
x2 + (kx + 1x) + 4 = 0

Reorder the terms:
4 + kx + 1x + x2 = 0

Solving
4 + kx + 1x + x2 = 0

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + kx + 1x + -4 + x2 = 0 + -4

Reorder the terms:
4 + -4 + kx + 1x + x2 = 0 + -4

Combine like terms: 4 + -4 = 0
0 + kx + 1x + x2 = 0 + -4
kx + 1x + x2 = 0 + -4

Combine like terms: 0 + -4 = -4
kx + 1x + x2 = -4

Add '-1x' to each side of the equation.
kx + 1x + -1x + x2 = -4 + -1x

Combine like terms: 1x + -1x = 0
kx + 0 + x2 = -4 + -1x
kx + x2 = -4 + -1x

Add '-1x2' to each side of the equation.
kx + x2 + -1x2 = -4 + -1x + -1x2

Combine like terms: x2 + -1x2 = 0
kx + 0 = -4 + -1x + -1x2
kx = -4 + -1x + -1x2

Divide each side by 'x'.
k = -4x-1 + -1 + -1x

Simplifying
k = -4x-1 + -1 + -1x

Reorder the terms:
k = -1 + -4x-1 + -1x

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